• Joe Harris
    6th/7th Grade Math
    Athletics
    jharris@cpsnj.org
    Voice Mail (908)735-0950 ext. 113
     
     
    6 GoMath - Home instruction
     
    6th grade GoMath assignment for Friday 4/3/20
     
    Login to my.hrw.com and complete the assignment "11.3 Multiplication and Division Equations - Interactive Student Lesson ".
    Assignment will be available from 8 AM until 9 PM.
    Be sure to click "Submit" so you can get credit for the assignment!
    Feel free to email with any questions.

     
    7 Pre-Algebra - Home instruction
     
    7th grade Pre-Algebra assignment for Friday 4/3/20
     

    Read Lesson 12.3 p. 465-467 in your textbook.

    Read all of the examples, and try the "Quick Checks" #1, #2, and #3 (answers below).

    Complete the textbook problems on p. 468-469 #5-30 and then use your answer key to check answers.

    VERY IMPORTANT : a prism is a 3-D shape with 2 opposite and congruent bases, and is NAMED by its base.  So, a rectangular prism has rectangular bases; a triangular prism has triangular bases; a hexagonal prism has hexagonal bases; a square prism (cube) has square bases; a circular prism (cylinder) has circular bases, etc.

    Feel free to email with any questions.

     

    Quick check answers:
     
    1. If the height of the prism is doubled, the new height would be 10 in.
    The formula for Volume of ANY prism is (B)(h), where B is the area of the base, and h is the distance between the bases.
    So the volume would be (3)(4)(10) = 120 cubic inches
     
    2. Always remember that the height of ANY prism is actually the distance between the bases, so the height of this triangular prism is 6 cm.
    If we double the height, the new height is 12 cm.
    Since this is a triangular prism, the base is a triangle, so B stands for area of the triangle, or (1/2)(base of triangle)(height of trangle).
    So B = (1/2)(3)(4), and h is 12, so V = (1/2)(3)(4)(12) = 72 cubic cm
     
    3a. A cylinder is really just a prism with circular bases.
    So the Volume of a cylinder = (area of circle)(distance between the 2 circles)
    In this problem, V = (pi)(9 squared)(24) = about 6107 cubic cm
     
    3b. No, if you use 20 instead of 16, your estimate would be too big.
     
     

     
     

     
Last Modified on Thursday at 8:17 PM